Base | Representation |
---|---|
bin | 111110000101000010… |
… | …1001010000011110101 |
3 | 110202002211010200111021 |
4 | 1330022011022003311 |
5 | 4141011124012021 |
6 | 141124310341141 |
7 | 12426423511642 |
oct | 1741205120365 |
9 | 422084120437 |
10 | 133313110261 |
11 | 515a0858991 |
12 | 21a0635a7b1 |
13 | c7573c72c6 |
14 | 66494d8dc9 |
15 | 3703b55c41 |
hex | 1f0a14a0f5 |
133313110261 has 2 divisors, whose sum is σ = 133313110262. Its totient is φ = 133313110260.
The previous prime is 133313110247. The next prime is 133313110327. The reversal of 133313110261 is 162011313331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 72455180625 + 60857929636 = 269175^2 + 246694^2 .
It is a cyclic number.
It is not a de Polignac number, because 133313110261 - 223 = 133304721653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133313110061) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656555130 + 66656555131.
It is an arithmetic number, because the mean of its divisors is an integer number (66656555131).
Almost surely, 2133313110261 is an apocalyptic number.
It is an amenable number.
133313110261 is a deficient number, since it is larger than the sum of its proper divisors (1).
133313110261 is an equidigital number, since it uses as much as digits as its factorization.
133313110261 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 133313110261 its reverse (162011313331), we get a palindrome (295324423592).
The spelling of 133313110261 in words is "one hundred thirty-three billion, three hundred thirteen million, one hundred ten thousand, two hundred sixty-one".
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