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133313212453 is a prime number
BaseRepresentation
bin111110000101000010…
…1100011000000100101
3110202002211022212200011
41330022011203000211
54141011140244303
6141124312450221
712426424415611
oct1741205430045
9422084285604
10133313212453
11515a0918743
1221a063a9971
13c757431985
146649524341
153703b7616d
hex1f0a163025

133313212453 has 2 divisors, whose sum is σ = 133313212454. Its totient is φ = 133313212452.

The previous prime is 133313212451. The next prime is 133313212469. The reversal of 133313212453 is 354212313331.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 128449126404 + 4864086049 = 358398^2 + 69743^2 .

It is a cyclic number.

It is not a de Polignac number, because 133313212453 - 21 = 133313212451 is a prime.

It is a super-2 number, since 2×1333132124532 (a number of 23 digits) contains 22 as substring.

Together with 133313212451, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133313212451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66656606226 + 66656606227.

It is an arithmetic number, because the mean of its divisors is an integer number (66656606227).

Almost surely, 2133313212453 is an apocalyptic number.

It is an amenable number.

133313212453 is a deficient number, since it is larger than the sum of its proper divisors (1).

133313212453 is an equidigital number, since it uses as much as digits as its factorization.

133313212453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 19440, while the sum is 31.

Adding to 133313212453 its reverse (354212313331), we get a palindrome (487525525784).

The spelling of 133313212453 in words is "one hundred thirty-three billion, three hundred thirteen million, two hundred twelve thousand, four hundred fifty-three".