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13331413234141 is a prime number
BaseRepresentation
bin1100000111111111011000…
…1001100111000111011101
31202012110201002222012011221
43001333312021213013131
53221410213241443031
644204211112213341
72544106563535042
oct301776611470735
952173632865157
1013331413234141
11427a903248822
1215b387339a251
137591ba8b2522
1434135b16b1c9
15181ba9a7aa11
hexc1ff62671dd

13331413234141 has 2 divisors, whose sum is σ = 13331413234142. Its totient is φ = 13331413234140.

The previous prime is 13331413234133. The next prime is 13331413234151. The reversal of 13331413234141 is 14143231413331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12365033796025 + 966379438116 = 3516395^2 + 983046^2 .

It is a cyclic number.

It is not a de Polignac number, because 13331413234141 - 23 = 13331413234133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13331413234097 and 13331413234106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13331413234151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665706617070 + 6665706617071.

It is an arithmetic number, because the mean of its divisors is an integer number (6665706617071).

Almost surely, 213331413234141 is an apocalyptic number.

It is an amenable number.

13331413234141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13331413234141 is an equidigital number, since it uses as much as digits as its factorization.

13331413234141 is an evil number, because the sum of its binary digits is even.

The product of its digits is 31104, while the sum is 34.

Adding to 13331413234141 its reverse (14143231413331), we get a palindrome (27474644647472).

The spelling of 13331413234141 in words is "thirteen trillion, three hundred thirty-one billion, four hundred thirteen million, two hundred thirty-four thousand, one hundred forty-one".