Base | Representation |
---|---|
bin | 1100000111111111011000… |
… | …1001100111000111011100 |
3 | 1202012110201002222012011220 |
4 | 3001333312021213013130 |
5 | 3221410213241443030 |
6 | 44204211112213340 |
7 | 2544106563535041 |
oct | 301776611470734 |
9 | 52173632865156 |
10 | 13331413234140 |
11 | 427a903248821 |
12 | 15b387339a250 |
13 | 7591ba8b2521 |
14 | 34135b16b1c8 |
15 | 181ba9a7aa10 |
hex | c1ff62671dc |
13331413234140 has 24 divisors (see below), whose sum is σ = 37327957055760. Its totient is φ = 3555043529088.
The previous prime is 13331413234133. The next prime is 13331413234141. The reversal of 13331413234140 is 4143231413331.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13331413234141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 111095110225 + ... + 111095110344.
It is an arithmetic number, because the mean of its divisors is an integer number (1555331543990).
Almost surely, 213331413234140 is an apocalyptic number.
13331413234140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13331413234140 is an abundant number, since it is smaller than the sum of its proper divisors (23996543821620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13331413234140 is a wasteful number, since it uses less digits than its factorization.
13331413234140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 222190220581 (or 222190220579 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 13331413234140 its reverse (4143231413331), we get a palindrome (17474644647471).
The spelling of 13331413234140 in words is "thirteen trillion, three hundred thirty-one billion, four hundred thirteen million, two hundred thirty-four thousand, one hundred forty".
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