Base | Representation |
---|---|
bin | 1100000111111111011010… |
… | …1100101000000111111111 |
3 | 1202012110201202020112122012 |
4 | 3001333312230220013333 |
5 | 3221410223114211221 |
6 | 44204212041041435 |
7 | 2544110034545342 |
oct | 301776654500777 |
9 | 52173652215565 |
10 | 13331422413311 |
11 | 427a908448212 |
12 | 15b387648627b |
13 | 7591bc7775a2 |
14 | 34135c47a459 |
15 | 181baa79065b |
hex | c1ff6b281ff |
13331422413311 has 2 divisors, whose sum is σ = 13331422413312. Its totient is φ = 13331422413310.
The previous prime is 13331422413277. The next prime is 13331422413343. The reversal of 13331422413311 is 11331422413331.
It is an a-pointer prime, because the next prime (13331422413343) can be obtained adding 13331422413311 to its sum of digits (32).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13331422413311 - 226 = 13331355304447 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13331422413391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6665711206655 + 6665711206656.
It is an arithmetic number, because the mean of its divisors is an integer number (6665711206656).
Almost surely, 213331422413311 is an apocalyptic number.
13331422413311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13331422413311 is an equidigital number, since it uses as much as digits as its factorization.
13331422413311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15552, while the sum is 32.
Adding to 13331422413311 its reverse (11331422413331), we get a palindrome (24662844826642).
The spelling of 13331422413311 in words is "thirteen trillion, three hundred thirty-one billion, four hundred twenty-two million, four hundred thirteen thousand, three hundred eleven".
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