Base | Representation |
---|---|
bin | 11110010100000101001000… |
… | …101111000011110100111010 |
3 | 122111001101120122011100211121 |
4 | 132110011020233003310322 |
5 | 114433314010313144010 |
6 | 1151314543150215454 |
7 | 40040101050052666 |
oct | 3624051057036472 |
9 | 574041518140747 |
10 | 133321300131130 |
11 | 39531278276a61 |
12 | 12b526897b458a |
13 | 59511b5a71177 |
14 | 24ccadd0358a6 |
15 | 1062ed64313da |
hex | 794148bc3d3a |
133321300131130 has 32 divisors (see below), whose sum is σ = 244062201055680. Its totient is φ = 52421117139840.
The previous prime is 133321300131121. The next prime is 133321300131163. The reversal of 133321300131130 is 31131003123331.
It is a junction number, because it is equal to n+sod(n) for n = 133321300131095 and 133321300131104.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1171870 + ... + 16371190.
It is an arithmetic number, because the mean of its divisors is an integer number (7626943782990).
Almost surely, 2133321300131130 is an apocalyptic number.
133321300131130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133321300131130 is a deficient number, since it is larger than the sum of its proper divisors (110740900924550).
133321300131130 is a wasteful number, since it uses less digits than its factorization.
133321300131130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15214254.
The product of its (nonzero) digits is 1458, while the sum is 25.
Adding to 133321300131130 its reverse (31131003123331), we get a palindrome (164452303254461).
The spelling of 133321300131130 in words is "one hundred thirty-three trillion, three hundred twenty-one billion, three hundred million, one hundred thirty-one thousand, one hundred thirty".
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