Base | Representation |
---|---|
bin | 1100001000000101010011… |
… | …0100000011110011100000 |
3 | 1202012121210210102101121102 |
4 | 3002001110310003303200 |
5 | 3221421441330420000 |
6 | 44205032444413532 |
7 | 2544164130101363 |
oct | 302012464036340 |
9 | 52177723371542 |
10 | 13333001420000 |
11 | 4280548790319 |
12 | 15b40372472a8 |
13 | 7593b193ca82 |
14 | 34146c0680da |
15 | 181c4e1e43d5 |
hex | c2054d03ce0 |
13333001420000 has 120 divisors (see below), whose sum is σ = 33859287709632. Its totient is φ = 5161161600000.
The previous prime is 13333001419993. The next prime is 13333001420003. The reversal of 13333001420000 is 2410033331.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13333001420003) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 10132421 + ... + 11372420.
Almost surely, 213333001420000 is an apocalyptic number.
13333001420000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13333001420000 is an abundant number, since it is smaller than the sum of its proper divisors (20526286289632).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13333001420000 is an equidigital number, since it uses as much as digits as its factorization.
13333001420000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21504902 (or 21504879 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 20.
Adding to 13333001420000 its reverse (2410033331), we get a palindrome (13335411453331).
The spelling of 13333001420000 in words is "thirteen trillion, three hundred thirty-three billion, one million, four hundred twenty thousand".
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