Base | Representation |
---|---|
bin | 10011011001101111011… |
… | …110011110010010101100 |
3 | 11201110111200012221011020 |
4 | 103121233132132102230 |
5 | 133321104342334012 |
6 | 2500303023054140 |
7 | 165220445015223 |
oct | 23315736362254 |
9 | 4643450187136 |
10 | 1333310121132 |
11 | 4744a9893220 |
12 | 1964a2a41350 |
13 | 989661a65a2 |
14 | 48765485cba |
15 | 24a38450a8c |
hex | 1366f79e4ac |
1333310121132 has 48 divisors (see below), whose sum is σ = 3476657890944. Its totient is φ = 394178896000.
The previous prime is 1333310121131. The next prime is 1333310121149. The reversal of 1333310121132 is 2311210133331.
It is a super-2 number, since 2×13333101211322 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1333310121131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 123175494 + ... + 123186317.
It is an arithmetic number, because the mean of its divisors is an integer number (72430372728).
Almost surely, 21333310121132 is an apocalyptic number.
1333310121132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
1333310121132 is an abundant number, since it is smaller than the sum of its proper divisors (2143347769812).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1333310121132 is a wasteful number, since it uses less digits than its factorization.
1333310121132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 246361870 (or 246361868 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 1333310121132 its reverse (2311210133331), we get a palindrome (3644520254463).
The spelling of 1333310121132 in words is "one trillion, three hundred thirty-three billion, three hundred ten million, one hundred twenty-one thousand, one hundred thirty-two".
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