Base | Representation |
---|---|
bin | 1100001000000110000011… |
… | …1001101001010111000100 |
3 | 1202012122022221000020202101 |
4 | 3002001200321221113010 |
5 | 3221422400234224030 |
6 | 44205104531121444 |
7 | 2544202141562242 |
oct | 302014071512704 |
9 | 52178287006671 |
10 | 13333204211140 |
11 | 42806421aa300 |
12 | 15b4093143284 |
13 | 759414963628 |
14 | 34148ad75792 |
15 | 181c61e007ca |
hex | c2060e695c4 |
13333204211140 has 72 divisors (see below), whose sum is σ = 32396380591680. Its totient is φ = 4593256937280.
The previous prime is 13333204211087. The next prime is 13333204211141. The reversal of 13333204211140 is 4111240233331.
It is a super-2 number, since 2×133332042111402 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13333204211099 and 13333204211108.
It is not an unprimeable number, because it can be changed into a prime (13333204211141) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 144943192 + ... + 145035151.
It is an arithmetic number, because the mean of its divisors is an integer number (449949730440).
Almost surely, 213333204211140 is an apocalyptic number.
13333204211140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13333204211140 is an abundant number, since it is smaller than the sum of its proper divisors (19063176380540).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13333204211140 is a wasteful number, since it uses less digits than its factorization.
13333204211140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 289978393 (or 289978380 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 13333204211140 its reverse (4111240233331), we get a palindrome (17444444444471).
The spelling of 13333204211140 in words is "thirteen trillion, three hundred thirty-three billion, two hundred four million, two hundred eleven thousand, one hundred forty".
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