Base | Representation |
---|---|
bin | 1100001000000110111000… |
… | …0001101001100110101100 |
3 | 1202012122220021100200001112 |
4 | 3002001232001221212230 |
5 | 3221423323122204400 |
6 | 44205142434531152 |
7 | 2544210454346411 |
oct | 302015601514654 |
9 | 52178807320045 |
10 | 13333424413100 |
11 | 42807455302a0 |
12 | 15b4134a36ab8 |
13 | 75944b471c4c |
14 | 3414ac2d6108 |
15 | 181c763ea835 |
hex | c206e0699ac |
13333424413100 has 72 divisors (see below), whose sum is σ = 31876365625776. Its totient is φ = 4800512800000.
The previous prime is 13333424413021. The next prime is 13333424413121. The reversal of 13333424413100 is 131442433331.
It is a happy number.
It is a super-2 number, since 2×133334244131002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 59895311 + ... + 60117510.
It is an arithmetic number, because the mean of its divisors is an integer number (442727300358).
Almost surely, 213333424413100 is an apocalyptic number.
13333424413100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13333424413100 is an abundant number, since it is smaller than the sum of its proper divisors (18542941212676).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13333424413100 is a wasteful number, since it uses less digits than its factorization.
13333424413100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120012947 (or 120012940 counting only the distinct ones).
The product of its (nonzero) digits is 31104, while the sum is 32.
Adding to 13333424413100 its reverse (131442433331), we get a palindrome (13464866846431).
The spelling of 13333424413100 in words is "thirteen trillion, three hundred thirty-three billion, four hundred twenty-four million, four hundred thirteen thousand, one hundred".
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