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13340422204271 is a prime number
BaseRepresentation
bin1100001000100000111100…
…1000000110101101101111
31202020022221221221021220022
43002020033020012231233
53222032141041014041
644212301053512355
72544546045526061
oct302101710065557
952208857837808
1013340422204271
114283706606388
1215b55684a26bb
13759cc5183696
14341973839731
1518203592a24b
hexc220f206b6f

13340422204271 has 2 divisors, whose sum is σ = 13340422204272. Its totient is φ = 13340422204270.

The previous prime is 13340422204217. The next prime is 13340422204273. The reversal of 13340422204271 is 17240222404331.

It is a happy number.

Together with previous prime (13340422204217) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (17240222404331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13340422204271 - 222 = 13340418009967 is a prime.

Together with 13340422204273, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13340422204273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6670211102135 + 6670211102136.

It is an arithmetic number, because the mean of its divisors is an integer number (6670211102136).

Almost surely, 213340422204271 is an apocalyptic number.

13340422204271 is a deficient number, since it is larger than the sum of its proper divisors (1).

13340422204271 is an equidigital number, since it uses as much as digits as its factorization.

13340422204271 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64512, while the sum is 35.

The spelling of 13340422204271 in words is "thirteen trillion, three hundred forty billion, four hundred twenty-two million, two hundred four thousand, two hundred seventy-one".