Base | Representation |
---|---|
bin | 11110010110111000100111… |
… | …011100010101000001001000 |
3 | 122111201211000021101011201021 |
4 | 132112320213130111001020 |
5 | 114444443200331213000 |
6 | 1151543254121002224 |
7 | 40060032521220052 |
oct | 3626704734250110 |
9 | 574654007334637 |
10 | 133514015101000 |
11 | 395a5a809041a6 |
12 | 12b83ab1623374 |
13 | 59664189cb311 |
14 | 24d81817a28d2 |
15 | 106801503811a |
hex | 796e27715048 |
133514015101000 has 64 divisors (see below), whose sum is σ = 313992759600000. Its totient is φ = 53137236081600.
The previous prime is 133514015100997. The next prime is 133514015101031. The reversal of 133514015101000 is 101510415331.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 335263350 + ... + 335661349.
It is an arithmetic number, because the mean of its divisors is an integer number (4906136868750).
Almost surely, 2133514015101000 is an apocalyptic number.
133514015101000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
133514015101000 is an abundant number, since it is smaller than the sum of its proper divisors (180478744499000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133514015101000 is a wasteful number, since it uses less digits than its factorization.
133514015101000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 670924919 (or 670924905 counting only the distinct ones).
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 133514015101000 its reverse (101510415331), we get a palindrome (133615525516331).
The spelling of 133514015101000 in words is "one hundred thirty-three trillion, five hundred fourteen billion, fifteen million, one hundred one thousand".
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