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13353410252207 is a prime number
BaseRepresentation
bin1100001001010001010101…
…0001100100110110101111
31202021120111010020111012202
43002110111101210312233
53222240241011032312
644222245540452115
72545515645234044
oct302242521446657
952246433214182
1013353410252207
114289170a67aa3
1215b7b920aa03b
1375b2b4c2c14c
143424467731cb
15182545cba9c2
hexc2515464daf

13353410252207 has 2 divisors, whose sum is σ = 13353410252208. Its totient is φ = 13353410252206.

The previous prime is 13353410252201. The next prime is 13353410252213. The reversal of 13353410252207 is 70225201435331.

It is a balanced prime because it is at equal distance from previous prime (13353410252201) and next prime (13353410252213).

It is a cyclic number.

It is not a de Polignac number, because 13353410252207 - 212 = 13353410248111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353410252201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676705126103 + 6676705126104.

It is an arithmetic number, because the mean of its divisors is an integer number (6676705126104).

Almost surely, 213353410252207 is an apocalyptic number.

13353410252207 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353410252207 is an equidigital number, since it uses as much as digits as its factorization.

13353410252207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 151200, while the sum is 38.

Adding to 13353410252207 its reverse (70225201435331), we get a palindrome (83578611687538).

The spelling of 13353410252207 in words is "thirteen trillion, three hundred fifty-three billion, four hundred ten million, two hundred fifty-two thousand, two hundred seven".