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13353450043229 is a prime number
BaseRepresentation
bin1100001001010001011110…
…1001010111011101011101
31202021120120220010002020022
43002110113221113131131
53222240331202340404
644222253521401525
72545516640401622
oct302242751273535
952246526102208
1013353450043229
11428919147563a
1215b7ba34992a5
1375b2c025182a
1434244bb70349
1518254952a8be
hexc2517a5775d

13353450043229 has 2 divisors, whose sum is σ = 13353450043230. Its totient is φ = 13353450043228.

The previous prime is 13353450043181. The next prime is 13353450043231. The reversal of 13353450043229 is 92234005435331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13040750995204 + 312699048025 = 3611198^2 + 559195^2 .

It is a cyclic number.

It is not a de Polignac number, because 13353450043229 - 236 = 13284730566493 is a prime.

Together with 13353450043231, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13353450043229.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13353450043289) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6676725021614 + 6676725021615.

It is an arithmetic number, because the mean of its divisors is an integer number (6676725021615).

Almost surely, 213353450043229 is an apocalyptic number.

It is an amenable number.

13353450043229 is a deficient number, since it is larger than the sum of its proper divisors (1).

13353450043229 is an equidigital number, since it uses as much as digits as its factorization.

13353450043229 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 44.

The spelling of 13353450043229 in words is "thirteen trillion, three hundred fifty-three billion, four hundred fifty million, forty-three thousand, two hundred twenty-nine".