Base | Representation |
---|---|
bin | 1100001001010110010000… |
… | …1110010001100111011111 |
3 | 1202021200220102120211102101 |
4 | 3002111210032101213133 |
5 | 3222300444101141124 |
6 | 44223025214105531 |
7 | 2545563530501452 |
oct | 302254416214737 |
9 | 52250812524371 |
10 | 13354734787039 |
11 | 42897906a2688 |
12 | 15b82a17ab2a7 |
13 | 75b466477679 |
14 | 34253063d499 |
15 | 1825c2205644 |
hex | c25643919df |
13354734787039 has 2 divisors, whose sum is σ = 13354734787040. Its totient is φ = 13354734787038.
The previous prime is 13354734787003. The next prime is 13354734787057. The reversal of 13354734787039 is 93078743745331.
It is a happy number.
13354734787039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13354734787039 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13354734787099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6677367393519 + 6677367393520.
It is an arithmetic number, because the mean of its divisors is an integer number (6677367393520).
Almost surely, 213354734787039 is an apocalyptic number.
13354734787039 is a deficient number, since it is larger than the sum of its proper divisors (1).
13354734787039 is an equidigital number, since it uses as much as digits as its factorization.
13354734787039 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 160030080, while the sum is 64.
The spelling of 13354734787039 in words is "thirteen trillion, three hundred fifty-four billion, seven hundred thirty-four million, seven hundred eighty-seven thousand, thirty-nine".
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