Search a number
-
+
133557150 = 23527312197
BaseRepresentation
bin1111111010111…
…10101110011110
3100022022101222010
413331132232132
5233142312100
621130332050
73211134306
oct775365636
9308271863
10133557150
1169431511
123888a026
13218928cc
1413a48606
15bad2750
hex7f5eb9e

133557150 has 48 divisors (see below), whose sum is σ = 335786544. Its totient is φ = 35124480.

The previous prime is 133557133. The next prime is 133557167. The reversal of 133557150 is 51755331.

It is an interprime number because it is at equal distance from previous prime (133557133) and next prime (133557167).

It is a super-2 number, since 2×1335571502 = 35675024632245000, which contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4852 + ... + 17048.

It is an arithmetic number, because the mean of its divisors is an integer number (6995553).

Almost surely, 2133557150 is an apocalyptic number.

133557150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 133557150, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167893272).

133557150 is an abundant number, since it is smaller than the sum of its proper divisors (202229394).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133557150 is a wasteful number, since it uses less digits than its factorization.

133557150 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12285 (or 12280 counting only the distinct ones).

The product of its (nonzero) digits is 7875, while the sum is 30.

The square root of 133557150 is about 11556.6928660409. The cubic root of 133557150 is about 511.1586498351.

It can be divided in two parts, 1335 and 57150, that added together give a palindrome (58485).

The spelling of 133557150 in words is "one hundred thirty-three million, five hundred fifty-seven thousand, one hundred fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 73 75 146 150 219 365 438 730 1095 1825 2190 3650 5475 10950 12197 24394 36591 60985 73182 121970 182955 304925 365910 609850 890381 914775 1780762 1829550 2671143 4451905 5342286 8903810 13355715 22259525 26711430 44519050 66778575 133557150