Base | Representation |
---|---|
bin | 1100001001011111010100… |
… | …1110110110000101010000 |
3 | 1202021221011222102012021222 |
4 | 3002113311032312011100 |
5 | 3222320434403221340 |
6 | 44224110442304212 |
7 | 2546011031365142 |
oct | 302276516660520 |
9 | 52257158365258 |
10 | 13357167632720 |
11 | 428a8199a964a |
12 | 15b88604b8068 |
13 | 75b7634c3622 |
14 | 3426c17acc92 |
15 | 1826b5ab88b5 |
hex | c25f53b6150 |
13357167632720 has 40 divisors (see below), whose sum is σ = 31067094599520. Its totient is φ = 5340857616000.
The previous prime is 13357167632713. The next prime is 13357167632723. The reversal of 13357167632720 is 2723676175331.
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13357167632723) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31183406 + ... + 31608845.
It is an arithmetic number, because the mean of its divisors is an integer number (776677364988).
Almost surely, 213357167632720 is an apocalyptic number.
13357167632720 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13357167632720 is an abundant number, since it is smaller than the sum of its proper divisors (17709926966800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13357167632720 is a wasteful number, since it uses less digits than its factorization.
13357167632720 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62794923 (or 62794917 counting only the distinct ones).
The product of its (nonzero) digits is 6667920, while the sum is 53.
The spelling of 13357167632720 in words is "thirteen trillion, three hundred fifty-seven billion, one hundred sixty-seven million, six hundred thirty-two thousand, seven hundred twenty".
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