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1337814107741 is a prime number
BaseRepresentation
bin10011011101111011111…
…011110100011001011101
311201220010120021011021002
4103131323323310121131
5133404320402421431
62502325555120045
7165440165201426
oct23357373643135
94656116234232
101337814107741
11476400207001
1219733b2a3025
1399203347817
1448a7170c64d
1524beda7a3cb
hex1377bef465d

1337814107741 has 2 divisors, whose sum is σ = 1337814107742. Its totient is φ = 1337814107740.

The previous prime is 1337814107737. The next prime is 1337814107743. The reversal of 1337814107741 is 1477014187331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 912494920516 + 425319187225 = 955246^2 + 652165^2 .

It is a cyclic number.

It is not a de Polignac number, because 1337814107741 - 22 = 1337814107737 is a prime.

It is a super-2 number, since 2×13378141077412 (a number of 25 digits) contains 22 as substring.

Together with 1337814107743, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1337814107743) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 668907053870 + 668907053871.

It is an arithmetic number, because the mean of its divisors is an integer number (668907053871).

Almost surely, 21337814107741 is an apocalyptic number.

It is an amenable number.

1337814107741 is a deficient number, since it is larger than the sum of its proper divisors (1).

1337814107741 is an equidigital number, since it uses as much as digits as its factorization.

1337814107741 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 395136, while the sum is 47.

The spelling of 1337814107741 in words is "one trillion, three hundred thirty-seven billion, eight hundred fourteen million, one hundred seven thousand, seven hundred forty-one".