Base | Representation |
---|---|
bin | 1100001011001011101010… |
… | …0000010101011110001110 |
3 | 1202101201020120121212112110 |
4 | 3002302322200111132032 |
5 | 3223310013231224240 |
6 | 44245320153044450 |
7 | 2551060453145430 |
oct | 302627240253616 |
9 | 52351216555473 |
10 | 13386247133070 |
11 | 42a1091589669 |
12 | 16024170b6726 |
13 | 761418c65376 |
14 | 343c7d882650 |
15 | 1833189b6c80 |
hex | c2cba81578e |
13386247133070 has 64 divisors (see below), whose sum is σ = 36716946471936. Its totient is φ = 3059681721600.
The previous prime is 13386247133053. The next prime is 13386247133173. The reversal of 13386247133070 is 7033174268331.
It is a super-2 number, since 2×133862471330702 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 24127927 + ... + 24676493.
It is an arithmetic number, because the mean of its divisors is an integer number (573702288624).
Almost surely, 213386247133070 is an apocalyptic number.
13386247133070 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13386247133070 is an abundant number, since it is smaller than the sum of its proper divisors (23330699338866).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13386247133070 is a wasteful number, since it uses less digits than its factorization.
13386247133070 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 664785.
The product of its (nonzero) digits is 1524096, while the sum is 48.
The spelling of 13386247133070 in words is "thirteen trillion, three hundred eighty-six billion, two hundred forty-seven million, one hundred thirty-three thousand, seventy".
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