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1340013252550 = 25273828609293
BaseRepresentation
bin10011011111111111000…
…000111000111111000110
311202002210211100021210211
4103133333000320333012
5133423321343040200
62503332114310034
7165545530466350
oct23377700707706
94662724307724
101340013252550
11477329602055
1219785388831a
1399493b39b3b
1448bdd8060d0
1524ccbb78aba
hex137ff038fc6

1340013252550 has 24 divisors (see below), whose sum is σ = 2848485314736. Its totient is φ = 459433115040.

The previous prime is 1340013252421. The next prime is 1340013252569. The reversal of 1340013252550 is 552523100431.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1914304297 + ... + 1914304996.

It is an arithmetic number, because the mean of its divisors is an integer number (118686888114).

Almost surely, 21340013252550 is an apocalyptic number.

1340013252550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1340013252550 is an abundant number, since it is smaller than the sum of its proper divisors (1508472062186).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340013252550 is a wasteful number, since it uses less digits than its factorization.

1340013252550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3828609312 (or 3828609307 counting only the distinct ones).

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 1340013252550 its reverse (552523100431), we get a palindrome (1892536352981).

The spelling of 1340013252550 in words is "one trillion, three hundred forty billion, thirteen million, two hundred fifty-two thousand, five hundred fifty".

Divisors: 1 2 5 7 10 14 25 35 50 70 175 350 3828609293 7657218586 19143046465 26800265051 38286092930 53600530102 95715232325 134001325255 191430464650 268002650510 670006626275 1340013252550