134010144134213 has 2 divisors, whose sum is σ = 134010144134214. Its totient is φ = 134010144134212.

The previous prime is 134010144134189. The next prime is 134010144134219. The reversal of 134010144134213 is 312431441010431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124727842458244 + 9282301675969 = 11168162^2 + 3046687^2 .

It is a cyclic number.

It is not a de Polignac number, because 134010144134213 - 2¹⁰ = 134010144133189 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 134010144134213.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134010144134219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005072067106 + 67005072067107.

It is an arithmetic number, because the mean of its divisors is an integer number (67005072067107).

Almost surely, 2^{134010144134213} is an apocalyptic number.

It is an amenable number.

134010144134213 is a deficient number, since it is larger than the sum of its proper divisors (1).

134010144134213 is an equidigital number, since it uses as much as digits as its factorization.

134010144134213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 134010144134213 its reverse (312431441010431), we get a palindrome (446441585144644).

The spelling of 134010144134213 in words is "one hundred thirty-four trillion, ten billion, one hundred forty-four million, one hundred thirty-four thousand, two hundred thirteen".