Base | Representation |
---|---|
bin | 11110011110000111110111… |
… | …101100000000101111001000 |
3 | 122120111100220222110211221212 |
4 | 132132013313230000233020 |
5 | 120031120402102042300 |
6 | 1153004000122552252 |
7 | 40141002111106064 |
oct | 3636076754005710 |
9 | 576440828424855 |
10 | 134011430112200 |
11 | 39777a2369a313 |
12 | 13044390968688 |
13 | 59a12ba430904 |
14 | 251428b570aa4 |
15 | 1075e28c53935 |
hex | 79e1f7b00bc8 |
134011430112200 has 96 divisors (see below), whose sum is σ = 330877779832800. Its totient is φ = 50333869071360.
The previous prime is 134011430112199. The next prime is 134011430112251. The reversal of 134011430112200 is 2211034110431.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 155615582 + ... + 156474381.
It is an arithmetic number, because the mean of its divisors is an integer number (3446643539925).
Almost surely, 2134011430112200 is an apocalyptic number.
134011430112200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
134011430112200 is an abundant number, since it is smaller than the sum of its proper divisors (196866349720600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134011430112200 is a wasteful number, since it uses less digits than its factorization.
134011430112200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 312090111 (or 312090102 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 134011430112200 its reverse (2211034110431), we get a palindrome (136222464222631).
The spelling of 134011430112200 in words is "one hundred thirty-four trillion, eleven billion, four hundred thirty million, one hundred twelve thousand, two hundred".
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