134012043433110 has 64 divisors (see below), whose sum is σ = 321736538462400. Its totient is φ = 35724587077632.

The previous prime is 134012043433061. The next prime is 134012043433129. The reversal of 134012043433110 is 11334340210431.

It is a super-2 number, since 2×134012043433110² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1759643152 + ... + 1759719308.

It is an arithmetic number, because the mean of its divisors is an integer number (5027133413475).

Almost surely, 2^{134012043433110} is an apocalyptic number.

134012043433110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

134012043433110 is an abundant number, since it is smaller than the sum of its proper divisors (187724495029290).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134012043433110 is a wasteful number, since it uses less digits than its factorization.

134012043433110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 95025.

The product of its (nonzero) digits is 10368, while the sum is 30.

Adding to 134012043433110 its reverse (11334340210431), we get a palindrome (145346383643541).

The spelling of 134012043433110 in words is "one hundred thirty-four trillion, twelve billion, forty-three million, four hundred thirty-three thousand, one hundred ten".