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134012102311141 is a prime number
BaseRepresentation
bin11110011110001000011111…
…110000001111110011100101
3122120111102122211100002112221
4132132020133300033303211
5120031123241142424031
61153004150534312341
740141024552520545
oct3636103760176345
9576442584302487
10134012102311141
113977823908032a
1213044539ab86b1
1359a1396787b72
14251431294d325
151075e67c83a11
hex79e21fc0fce5

134012102311141 has 2 divisors, whose sum is σ = 134012102311142. Its totient is φ = 134012102311140.

The previous prime is 134012102311123. The next prime is 134012102311177. The reversal of 134012102311141 is 141113201210431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 132111691180225 + 1900411130916 = 11493985^2 + 1378554^2 .

It is an emirp because it is prime and its reverse (141113201210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134012102311141 - 217 = 134012102180069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134012102315141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006051155570 + 67006051155571.

It is an arithmetic number, because the mean of its divisors is an integer number (67006051155571).

Almost surely, 2134012102311141 is an apocalyptic number.

It is an amenable number.

134012102311141 is a deficient number, since it is larger than the sum of its proper divisors (1).

134012102311141 is an equidigital number, since it uses as much as digits as its factorization.

134012102311141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 134012102311141 its reverse (141113201210431), we get a palindrome (275125303521572).

The spelling of 134012102311141 in words is "one hundred thirty-four trillion, twelve billion, one hundred two million, three hundred eleven thousand, one hundred forty-one".