1340121437 has 2 divisors, whose sum is σ = 1340121438. Its totient is φ = 1340121436.

The previous prime is 1340121421. The next prime is 1340121451. The reversal of 1340121437 is 7341210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1106826361 + 233295076 = 33269^2 + 15274^2 .

It is an emirp because it is prime and its reverse (7341210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340121437 - 2⁴ = 1340121421 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340121467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060718 + 670060719.

It is an arithmetic number, because the mean of its divisors is an integer number (670060719).

Almost surely, 2^1340121437 is an apocalyptic number.

It is an amenable number.

1340121437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121437 is an equidigital number, since it uses as much as digits as its factorization.

1340121437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 26.

The square root of 1340121437 is about 36607.6691008865. The cubic root of 1340121437 is about 1102.5070742018.

Adding to 1340121437 its reverse (7341210431), we get a palindrome (8681331868).

The spelling of 1340121437 in words is "one billion, three hundred forty million, one hundred twenty-one thousand, four hundred thirty-seven".