Base | Representation |
---|---|
bin | 100111111100000… |
… | …1010000101101011 |
3 | 10110101200020000211 |
4 | 1033320022011223 |
5 | 10221032341301 |
6 | 340551241551 |
7 | 45131562424 |
oct | 11770120553 |
9 | 3411606024 |
10 | 1340121451 |
11 | 628511099 |
12 | 3149792b7 |
13 | 184844b96 |
14 | c9da664b |
15 | 7c9b8051 |
hex | 4fe0a16b |
1340121451 has 2 divisors, whose sum is σ = 1340121452. Its totient is φ = 1340121450.
The previous prime is 1340121437. The next prime is 1340121467. The reversal of 1340121451 is 1541210431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340121451 - 27 = 1340121323 is a prime.
It is not a weakly prime, because it can be changed into another prime (1340121401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060725 + 670060726.
It is an arithmetic number, because the mean of its divisors is an integer number (670060726).
Almost surely, 21340121451 is an apocalyptic number.
1340121451 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340121451 is an equidigital number, since it uses as much as digits as its factorization.
1340121451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 22.
The square root of 1340121451 is about 36607.6692921033. The cubic root of 1340121451 is about 1102.5070780410.
Adding to 1340121451 its reverse (1541210431), we get a palindrome (2881331882).
The spelling of 1340121451 in words is "one billion, three hundred forty million, one hundred twenty-one thousand, four hundred fifty-one".
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