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1340121467 is a prime number
BaseRepresentation
bin100111111100000…
…1010000101111011
310110101200020001102
41033320022011323
510221032341332
6340551242015
745131562446
oct11770120573
93411606042
101340121467
11628511103
1231497930b
13184844ba9
14c9da665d
157c9b8062
hex4fe0a17b

1340121467 has 2 divisors, whose sum is σ = 1340121468. Its totient is φ = 1340121466.

The previous prime is 1340121451. The next prime is 1340121469. The reversal of 1340121467 is 7641210431.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (7641210431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1340121467 - 24 = 1340121451 is a prime.

Together with 1340121469, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1340121469) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060733 + 670060734.

It is an arithmetic number, because the mean of its divisors is an integer number (670060734).

Almost surely, 21340121467 is an apocalyptic number.

1340121467 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121467 is an equidigital number, since it uses as much as digits as its factorization.

1340121467 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 29.

The square root of 1340121467 is about 36607.6695106367. The cubic root of 1340121467 is about 1102.5070824287.

Adding to 1340121467 its reverse (7641210431), we get a palindrome (8981331898).

The spelling of 1340121467 in words is "one billion, three hundred forty million, one hundred twenty-one thousand, four hundred sixty-seven".