1340122004413 has 2 divisors, whose sum is σ = 1340122004414. Its totient is φ = 1340122004412.

The previous prime is 1340122004383. The next prime is 1340122004447. The reversal of 1340122004413 is 3144002210431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1103251928164 + 236870076249 = 1050358^2 + 486693^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340122004413 - 2¹³ = 1340121996221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340122004453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670061002206 + 670061002207.

It is an arithmetic number, because the mean of its divisors is an integer number (670061002207).

Almost surely, 2^{1340122004413} is an apocalyptic number.

It is an amenable number.

1340122004413 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340122004413 is an equidigital number, since it uses as much as digits as its factorization.

1340122004413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1340122004413 its reverse (3144002210431), we get a palindrome (4484124214844).

The spelling of 1340122004413 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, four thousand, four hundred thirteen".