Base | Representation |
---|---|
bin | 10011100000000101011… |
… | …111101111101111011111 |
3 | 11202010002101222110100212 |
4 | 103200011133233233133 |
5 | 133424032213120242 |
6 | 2503351001243035 |
7 | 165551321042312 |
oct | 23400537575737 |
9 | 4663071873325 |
10 | 1340122004447 |
11 | 477384a30a56 |
12 | 19788419347b |
13 | 994b0526085 |
14 | 48c10034979 |
15 | 24cd64ab782 |
hex | 138057efbdf |
1340122004447 has 2 divisors, whose sum is σ = 1340122004448. Its totient is φ = 1340122004446.
The previous prime is 1340122004413. The next prime is 1340122004453. The reversal of 1340122004447 is 7444002210431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1340122004447 - 26 = 1340122004383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340122004477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670061002223 + 670061002224.
It is an arithmetic number, because the mean of its divisors is an integer number (670061002224).
Almost surely, 21340122004447 is an apocalyptic number.
1340122004447 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340122004447 is an equidigital number, since it uses as much as digits as its factorization.
1340122004447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 32.
Adding to 1340122004447 its reverse (7444002210431), we get a palindrome (8784124214878).
The spelling of 1340122004447 in words is "one trillion, three hundred forty billion, one hundred twenty-two million, four thousand, four hundred forty-seven".
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