Base | Representation |
---|---|
bin | 1100001100000011011100… |
… | …0001001100011000111011 |
3 | 1202110010220010122022100011 |
4 | 3003000313001030120323 |
5 | 3224031200040221131 |
6 | 44300234055322351 |
7 | 2552130515131153 |
oct | 303006701143073 |
9 | 52403803568304 |
10 | 13401221023291 |
11 | 42a7475997a52 |
12 | 16052b59803b7 |
13 | 76296426c03a |
14 | 3448a042b763 |
15 | 1838e33700b1 |
hex | c303704c63b |
13401221023291 has 2 divisors, whose sum is σ = 13401221023292. Its totient is φ = 13401221023290.
The previous prime is 13401221023261. The next prime is 13401221023397. The reversal of 13401221023291 is 19232012210431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13401221023291 - 27 = 13401221023163 is a prime.
It is not a weakly prime, because it can be changed into another prime (13401221023231) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700610511645 + 6700610511646.
It is an arithmetic number, because the mean of its divisors is an integer number (6700610511646).
Almost surely, 213401221023291 is an apocalyptic number.
13401221023291 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401221023291 is an equidigital number, since it uses as much as digits as its factorization.
13401221023291 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 31.
The spelling of 13401221023291 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-three thousand, two hundred ninety-one".
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