Base | Representation |
---|---|
bin | 1100001100000011011100… |
… | …0001001100011010100110 |
3 | 1202110010220010122022111010 |
4 | 3003000313001030122212 |
5 | 3224031200040222043 |
6 | 44300234055323050 |
7 | 2552130515131365 |
oct | 303006701143246 |
9 | 52403803568433 |
10 | 13401221023398 |
11 | 42a747599803a |
12 | 16052b5980486 |
13 | 76296426c0c0 |
14 | 3448a042b7dc |
15 | 1838e3370133 |
hex | c303704c6a6 |
13401221023398 has 64 divisors (see below), whose sum is σ = 30119835497472. Its totient is φ = 3944079976320.
The previous prime is 13401221023397. The next prime is 13401221023427. The reversal of 13401221023398 is 89332012210431.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (39).
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13401221023397) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 135471111 + ... + 135569997.
It is an arithmetic number, because the mean of its divisors is an integer number (470622429648).
Almost surely, 213401221023398 is an apocalyptic number.
13401221023398 is an abundant number, since it is smaller than the sum of its proper divisors (16718614474074).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13401221023398 is a wasteful number, since it uses less digits than its factorization.
13401221023398 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174469.
The product of its (nonzero) digits is 62208, while the sum is 39.
The spelling of 13401221023398 in words is "thirteen trillion, four hundred one billion, two hundred twenty-one million, twenty-three thousand, three hundred ninety-eight".
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