Base | Representation |
---|---|
bin | 10011100000000101100… |
… | …100000011111001000000 |
3 | 11202010002111002220221122 |
4 | 103200011210003321000 |
5 | 133424033010314202 |
6 | 2503351041411412 |
7 | 165551333463065 |
oct | 23400544037100 |
9 | 4663074086848 |
10 | 1340123135552 |
11 | 477385633853 |
12 | 197884639b68 |
13 | 994b0830b76 |
14 | 48c1024ac6c |
15 | 24cd66319a2 |
hex | 13805903e40 |
1340123135552 has 56 divisors (see below), whose sum is σ = 2804644571040. Its totient is φ = 633576453120.
The previous prime is 1340123135539. The next prime is 1340123135557. The reversal of 1340123135552 is 2555313210431.
It is a happy number.
It is not an unprimeable number, because it can be changed into a prime (1340123135557) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 424118 + ... + 1691189.
Almost surely, 21340123135552 is an apocalyptic number.
It is an amenable number.
1340123135552 is an abundant number, since it is smaller than the sum of its proper divisors (1464521435488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340123135552 is a wasteful number, since it uses less digits than its factorization.
1340123135552 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2115859 (or 2115849 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 35.
Adding to 1340123135552 its reverse (2555313210431), we get a palindrome (3895436345983).
The spelling of 1340123135552 in words is "one trillion, three hundred forty billion, one hundred twenty-three million, one hundred thirty-five thousand, five hundred fifty-two".
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