134012411343140 has 96 divisors (see below), whose sum is σ = 312615368303616. Its totient is φ = 47849288941440.

The previous prime is 134012411343121. The next prime is 134012411343149. The reversal of 134012411343140 is 41343114210431.

It is a happy number.

It is a junction number, because it is equal to n+sod(n) for n = 134012411343097 and 134012411343106.

It is not an unprimeable number, because it can be changed into a prime (134012411343149) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19536272 + ... + 25489031.

It is an arithmetic number, because the mean of its divisors is an integer number (3256410086496).

Almost surely, 2^{134012411343140} is an apocalyptic number.

134012411343140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

134012411343140 is an abundant number, since it is smaller than the sum of its proper divisors (178602956960476).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

134012411343140 is a wasteful number, since it uses less digits than its factorization.

134012411343140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45025569 (or 45025567 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 32.

Adding to 134012411343140 its reverse (41343114210431), we get a palindrome (175355525553571).

The spelling of 134012411343140 in words is "one hundred thirty-four trillion, twelve billion, four hundred eleven million, three hundred forty-three thousand, one hundred forty".