1340140211 has 2 divisors, whose sum is σ = 1340140212. Its totient is φ = 1340140210.

The previous prime is 1340140183. The next prime is 1340140213. The reversal of 1340140211 is 1120410431.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340140211 - 2⁶ = 1340140147 is a prime.

Together with 1340140213, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1340140211.

It is not a weakly prime, because it can be changed into another prime (1340140213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670070105 + 670070106.

It is an arithmetic number, because the mean of its divisors is an integer number (670070106).

Almost surely, 2^1340140211 is an apocalyptic number.

1340140211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340140211 is an equidigital number, since it uses as much as digits as its factorization.

1340140211 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1340140211 is about 36607.9255216681. The cubic root of 1340140211 is about 1102.5122225838.

Adding to 1340140211 its reverse (1120410431), we get a palindrome (2460550642).

The spelling of 1340140211 in words is "one billion, three hundred forty million, one hundred forty thousand, two hundred eleven".