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13401403034021 is a prime number
BaseRepresentation
bin1100001100000100000111…
…0111100000100110100101
31202110011100211010102010022
43003001001313200212211
53224032033134042041
644300304120404525
72552135155162532
oct303010167404645
952404324112108
1013401403034021
1142a7559703342
121605346916745
13762992b981b2
143448ba689d89
1518390432424b
hexc3041de09a5

13401403034021 has 2 divisors, whose sum is σ = 13401403034022. Its totient is φ = 13401403034020.

The previous prime is 13401403034009. The next prime is 13401403034023. The reversal of 13401403034021 is 12043030410431.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7229726104225 + 6171676929796 = 2688815^2 + 2484286^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401403034021 - 26 = 13401403033957 is a prime.

It is a Sophie Germain prime.

Together with 13401403034023, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401403034023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700701517010 + 6700701517011.

It is an arithmetic number, because the mean of its divisors is an integer number (6700701517011).

Almost surely, 213401403034021 is an apocalyptic number.

It is an amenable number.

13401403034021 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401403034021 is an equidigital number, since it uses as much as digits as its factorization.

13401403034021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 13401403034021 its reverse (12043030410431), we get a palindrome (25444433444452).

The spelling of 13401403034021 in words is "thirteen trillion, four hundred one billion, four hundred three million, thirty-four thousand, twenty-one".