Base | Representation |
---|---|
bin | 111110011001111100… |
… | …0011001110100010111 |
3 | 110210220200202101212221 |
4 | 1330303320121310113 |
5 | 4143430142110012 |
6 | 141322041523211 |
7 | 12453000455422 |
oct | 1746370316427 |
9 | 423820671787 |
10 | 134014410007 |
11 | 51920705855 |
12 | 21b811a3507 |
13 | c8397a017a |
14 | 66b46d09b9 |
15 | 37454d3507 |
hex | 1f33e19d17 |
134014410007 has 2 divisors, whose sum is σ = 134014410008. Its totient is φ = 134014410006.
The previous prime is 134014409987. The next prime is 134014410053. The reversal of 134014410007 is 700014410431.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134014410007 - 223 = 134006021399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134014410067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007205003 + 67007205004.
It is an arithmetic number, because the mean of its divisors is an integer number (67007205004).
Almost surely, 2134014410007 is an apocalyptic number.
134014410007 is a deficient number, since it is larger than the sum of its proper divisors (1).
134014410007 is an equidigital number, since it uses as much as digits as its factorization.
134014410007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 134014410007 its reverse (700014410431), we get a palindrome (834028820438).
The spelling of 134014410007 in words is "one hundred thirty-four billion, fourteen million, four hundred ten thousand, seven".
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