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1340193551 is a prime number
BaseRepresentation
bin100111111100001…
…1011101100001111
310110101210212221012
41033320123230033
510221042143201
6340552555435
745132312554
oct11770335417
93411725835
101340193551
11628560284
123149b2b7b
1318486b948
14c9dc4a2b
157c9ce5bb
hex4fe1bb0f

1340193551 has 2 divisors, whose sum is σ = 1340193552. Its totient is φ = 1340193550.

The previous prime is 1340193523. The next prime is 1340193553. The reversal of 1340193551 is 1553910431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340193551 is a prime.

It is a super-2 number, since 2×13401935512 = 3592237508283979202, which contains 22 as substring.

It is a Sophie Germain prime.

Together with 1340193553, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340193553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670096775 + 670096776.

It is an arithmetic number, because the mean of its divisors is an integer number (670096776).

Almost surely, 21340193551 is an apocalyptic number.

1340193551 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340193551 is an equidigital number, since it uses as much as digits as its factorization.

1340193551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 32.

The square root of 1340193551 is about 36608.6540451845. The cubic root of 1340193551 is about 1102.5268497154.

The spelling of 1340193551 in words is "one billion, three hundred forty million, one hundred ninety-three thousand, five hundred fifty-one".