134019791 has 2 divisors, whose sum is σ = 134019792. Its totient is φ = 134019790.

The previous prime is 134019757. The next prime is 134019793. The reversal of 134019791 is 197910431.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (197910431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134019791 - 2¹⁰ = 134018767 is a prime.

It is a super-2 number, since 2×134019791² = 35922608759367362, which contains 22 as substring.

Together with 134019793, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134019793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67009895 + 67009896.

It is an arithmetic number, because the mean of its divisors is an integer number (67009896).

Almost surely, 2^134019791 is an apocalyptic number.

134019791 is a deficient number, since it is larger than the sum of its proper divisors (1).

134019791 is an equidigital number, since it uses as much as digits as its factorization.

134019791 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6804, while the sum is 35.

The square root of 134019791 is about 11576.6917122294. The cubic root of 134019791 is about 511.7481862614.

The spelling of 134019791 in words is "one hundred thirty-four million, nineteen thousand, seven hundred ninety-one".