Base | Representation |
---|---|
bin | 11110011110001111111100… |
… | …110010000100101101011110 |
3 | 122120112012022120210022221110 |
4 | 132132033330302010231132 |
5 | 120031241134003201024 |
6 | 1153011553031042450 |
7 | 40141430102633055 |
oct | 3636177462045536 |
9 | 576465276708843 |
10 | 134020105522014 |
11 | 39780675741098 |
12 | 13045bb2210426 |
13 | 59a20708835ba |
14 | 251487181139c |
15 | 10762856b5629 |
hex | 79e3fcc84b5e |
134020105522014 has 64 divisors (see below), whose sum is σ = 285252192352512. Its totient is φ = 41831832000000.
The previous prime is 134020105522013. The next prime is 134020105522027. The reversal of 134020105522014 is 410225501020431.
It is a super-2 number, since 2×1340201055220142 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (134020105522013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20335264 + ... + 26106764.
It is an arithmetic number, because the mean of its divisors is an integer number (4457065505508).
Almost surely, 2134020105522014 is an apocalyptic number.
134020105522014 is an abundant number, since it is smaller than the sum of its proper divisors (151232086830498).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
134020105522014 is a wasteful number, since it uses less digits than its factorization.
134020105522014 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5772681.
The product of its (nonzero) digits is 9600, while the sum is 30.
Adding to 134020105522014 its reverse (410225501020431), we get a palindrome (544245606542445).
The spelling of 134020105522014 in words is "one hundred thirty-four trillion, twenty billion, one hundred five million, five hundred twenty-two thousand, fourteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •