1340204433431 has 2 divisors, whose sum is σ = 1340204433432. Its totient is φ = 1340204433430.

The previous prime is 1340204433389. The next prime is 1340204433433. The reversal of 1340204433431 is 1343344020431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1340204433431 - 2²² = 1340200239127 is a prime.

It is a super-2 number, since 2×1340204433431² (a number of 25 digits) contains 22 as substring.

Together with 1340204433433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340204433433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670102216715 + 670102216716.

It is an arithmetic number, because the mean of its divisors is an integer number (670102216716).

Almost surely, 2^{1340204433431} is an apocalyptic number.

1340204433431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340204433431 is an equidigital number, since it uses as much as digits as its factorization.

1340204433431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 41472, while the sum is 32.

Adding to 1340204433431 its reverse (1343344020431), we get a palindrome (2683548453862).

The spelling of 1340204433431 in words is "one trillion, three hundred forty billion, two hundred four million, four hundred thirty-three thousand, four hundred thirty-one".