134021101 has 2 divisors, whose sum is σ = 134021102. Its totient is φ = 134021100.

The previous prime is 134021099. The next prime is 134021143. The reversal of 134021101 is 101120431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86769225 + 47251876 = 9315^2 + 6874^2 .

It is an emirp because it is prime and its reverse (101120431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134021101 - 2¹ = 134021099 is a prime.

Together with 134021099, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134021201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010550 + 67010551.

It is an arithmetic number, because the mean of its divisors is an integer number (67010551).

Almost surely, 2^134021101 is an apocalyptic number.

It is an amenable number.

134021101 is a deficient number, since it is larger than the sum of its proper divisors (1).

134021101 is an equidigital number, since it uses as much as digits as its factorization.

134021101 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

The square root of 134021101 is about 11576.7482912949. The cubic root of 134021101 is about 511.7498536469.

Adding to 134021101 its reverse (101120431), we get a palindrome (235141532).

The spelling of 134021101 in words is "one hundred thirty-four million, twenty-one thousand, one hundred one".