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13403004523000 = 2353471378920681
BaseRepresentation
bin1100001100001010000101…
…0100101101000111111000
31202110022111102121110222221
43003002201110231013320
53224043323124214000
644301131050053424
72552222642463601
oct303024124550770
952408442543887
1013403004523000
1142a8200701754
12160571311a274
13762b89902901
143449cd24ada8
15183999c1961a
hexc30a152d1f8

13403004523000 has 128 divisors (see below), whose sum is σ = 32034200889600. Its totient is φ = 5246499456000.

The previous prime is 13403004522967. The next prime is 13403004523021. The reversal of 13403004523000 is 32540030431.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 648072660 + ... + 648093340.

It is an arithmetic number, because the mean of its divisors is an integer number (250267194450).

Almost surely, 213403004523000 is an apocalyptic number.

13403004523000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13403004523000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16017100444800).

13403004523000 is an abundant number, since it is smaller than the sum of its proper divisors (18631196366600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13403004523000 is a wasteful number, since it uses less digits than its factorization.

13403004523000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34538 (or 34524 counting only the distinct ones).

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 13403004523000 its reverse (32540030431), we get a palindrome (13435544553431).

The spelling of 13403004523000 in words is "thirteen trillion, four hundred three billion, four million, five hundred twenty-three thousand".

Divisors: 1 2 4 5 8 10 20 25 40 47 50 94 100 125 188 200 235 250 376 470 500 940 1000 1175 1880 2350 4700 5875 9400 11750 13789 20681 23500 27578 41362 47000 55156 68945 82724 103405 110312 137890 165448 206810 275780 344725 413620 517025 551560 648083 689450 827240 972007 1034050 1296166 1378900 1723625 1944014 2068100 2585125 2592332 2757800 3240415 3447250 3888028 4136200 4860035 5170250 5184664 6480830 6894500 7776056 9720070 10340500 12961660 13789000 16202075 19440140 20681000 24300175 25923320 32404150 38880280 48600350 64808300 81010375 97200700 121500875 129616600 162020750 194401400 243001750 285170309 324041500 486003500 570340618 648083000 972007000 1140681236 1425851545 2281362472 2851703090 5703406180 7129257725 11406812360 13403004523 14258515450 26806009046 28517030900 35646288625 53612018092 57034061800 67015022615 71292577250 107224036184 134030045230 142585154500 268060090460 285170309000 335075113075 536120180920 670150226150 1340300452300 1675375565375 2680600904600 3350751130750 6701502261500 13403004523000