Base | Representation |
---|---|
bin | 11000111101110001… |
… | …11011010011011101 |
3 | 1021121002101010102021 |
4 | 30132320323103131 |
5 | 204422201010331 |
6 | 10053551500141 |
7 | 653066551552 |
oct | 143670732335 |
9 | 37532333367 |
10 | 13403141341 |
11 | 57587a6517 |
12 | 2720827651 |
13 | 1357a73085 |
14 | 91210aa29 |
15 | 536a36211 |
hex | 31ee3b4dd |
13403141341 has 2 divisors, whose sum is σ = 13403141342. Its totient is φ = 13403141340.
The previous prime is 13403141267. The next prime is 13403141347. The reversal of 13403141341 is 14314130431.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12192797241 + 1210344100 = 110421^2 + 34790^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13403141341 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13403141347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701570670 + 6701570671.
It is an arithmetic number, because the mean of its divisors is an integer number (6701570671).
Almost surely, 213403141341 is an apocalyptic number.
It is an amenable number.
13403141341 is a deficient number, since it is larger than the sum of its proper divisors (1).
13403141341 is an equidigital number, since it uses as much as digits as its factorization.
13403141341 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 13403141341 its reverse (14314130431), we get a palindrome (27717271772).
The spelling of 13403141341 in words is "thirteen billion, four hundred three million, one hundred forty-one thousand, three hundred forty-one".
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