Base | Representation |
---|---|
bin | 11000111101110011… |
… | …00100100101001010 |
3 | 1021121002200201100002 |
4 | 30132321210211022 |
5 | 204422221413120 |
6 | 10053555243002 |
7 | 653101154510 |
oct | 143671444512 |
9 | 37532621302 |
10 | 13403310410 |
11 | 5758901546 |
12 | 27208a9462 |
13 | 1357b02009 |
14 | 9121524b0 |
15 | 536a6b375 |
hex | 31ee6494a |
13403310410 has 128 divisors (see below), whose sum is σ = 29874216960. Its totient is φ = 4227033600.
The previous prime is 13403310407. The next prime is 13403310419. The reversal of 13403310410 is 1401330431.
13403310410 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13403310419) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14777177 + ... + 14778083.
It is an arithmetic number, because the mean of its divisors is an integer number (233392320).
Almost surely, 213403310410 is an apocalyptic number.
13403310410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13403310410 is an abundant number, since it is smaller than the sum of its proper divisors (16470906550).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13403310410 is a wasteful number, since it uses less digits than its factorization.
13403310410 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1252.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13403310410 its reverse (1401330431), we get a palindrome (14804640841).
The spelling of 13403310410 in words is "thirteen billion, four hundred three million, three hundred ten thousand, four hundred ten".
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