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1340333103229 is a prime number
BaseRepresentation
bin10011100000010010000…
…101000001100001111101
311202010122010012101110021
4103200102011001201331
5133430000233300404
62503423542012141
7165556463253541
oct23402205014175
94663563171407
101340333103229
1147748310465a
12197922a17051
13995151980b3
1448c300a5a21
1524ce9ca9454
hex1381214187d

1340333103229 has 2 divisors, whose sum is σ = 1340333103230. Its totient is φ = 1340333103228.

The previous prime is 1340333103181. The next prime is 1340333103251. The reversal of 1340333103229 is 9223013330431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1299246624025 + 41086479204 = 1139845^2 + 202698^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340333103229 - 219 = 1340332578941 is a prime.

It is a super-2 number, since 2×13403331032292 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1340333103194 and 1340333103203.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340333103299) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670166551614 + 670166551615.

It is an arithmetic number, because the mean of its divisors is an integer number (670166551615).

Almost surely, 21340333103229 is an apocalyptic number.

It is an amenable number.

1340333103229 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340333103229 is an equidigital number, since it uses as much as digits as its factorization.

1340333103229 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 34992, while the sum is 34.

The spelling of 1340333103229 in words is "one trillion, three hundred forty billion, three hundred thirty-three million, one hundred three thousand, two hundred twenty-nine".