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1340333103181 is a prime number
BaseRepresentation
bin10011100000010010000…
…101000001100001001101
311202010122010012101101111
4103200102011001201031
5133430000233300211
62503423542012021
7165556463253442
oct23402205014115
94663563171344
101340333103181
11477483104616
12197922a17011
1399515198077
1448c300a59c9
1524ce9ca9421
hex1381214184d

1340333103181 has 2 divisors, whose sum is σ = 1340333103182. Its totient is φ = 1340333103180.

The previous prime is 1340333103133. The next prime is 1340333103229. The reversal of 1340333103181 is 1813013330431.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (1340333103133) and next prime (1340333103229).

It can be written as a sum of positive squares in only one way, i.e., 740236536900 + 600096566281 = 860370^2 + 774659^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340333103181 - 217 = 1340332972109 is a prime.

It is a super-2 number, since 2×13403331031812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340333143181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670166551590 + 670166551591.

It is an arithmetic number, because the mean of its divisors is an integer number (670166551591).

Almost surely, 21340333103181 is an apocalyptic number.

It is an amenable number.

1340333103181 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340333103181 is an equidigital number, since it uses as much as digits as its factorization.

1340333103181 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7776, while the sum is 31.

The spelling of 1340333103181 in words is "one trillion, three hundred forty billion, three hundred thirty-three million, one hundred three thousand, one hundred eighty-one".