Base | Representation |
---|---|
bin | 11000111101110011… |
… | …11101001111110000 |
3 | 1021121002212211220221 |
4 | 30132321331033300 |
5 | 204422233131230 |
6 | 10054001342424 |
7 | 653102055166 |
oct | 143671751760 |
9 | 37532784827 |
10 | 13403411440 |
11 | 5758970441 |
12 | 2720937a14 |
13 | 1357b38cb3 |
14 | 91217b236 |
15 | 536a8b27a |
hex | 31ee7d3f0 |
13403411440 has 80 divisors (see below), whose sum is σ = 31449049632. Its totient is φ = 5312294912.
The previous prime is 13403411423. The next prime is 13403411501. The reversal of 13403411440 is 4411430431.
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9392007 + ... + 9393433.
Almost surely, 213403411440 is an apocalyptic number.
13403411440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13403411440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15724524816).
13403411440 is an abundant number, since it is smaller than the sum of its proper divisors (18045638192).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13403411440 is a wasteful number, since it uses less digits than its factorization.
13403411440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2434 (or 2428 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 13403411440 its reverse (4411430431), we get a palindrome (17814841871).
The spelling of 13403411440 in words is "thirteen billion, four hundred three million, four hundred eleven thousand, four hundred forty".
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