134043320221 has 2 divisors, whose sum is σ = 134043320222. Its totient is φ = 134043320220.

The previous prime is 134043320209. The next prime is 134043320233. The reversal of 134043320221 is 122023340431.

It is a balanced prime because it is at equal distance from previous prime (134043320209) and next prime (134043320233).

It can be written as a sum of positive squares in only one way, i.e., 96341331321 + 37701988900 = 310389^2 + 194170^2 .

It is an emirp because it is prime and its reverse (122023340431) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 134043320221 - 2¹⁵ = 134043287453 is a prime.

It is a super-2 number, since 2×134043320221² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134043320261) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67021660110 + 67021660111.

It is an arithmetic number, because the mean of its divisors is an integer number (67021660111).

Almost surely, 2^134043320221 is an apocalyptic number.

It is an amenable number.

134043320221 is a deficient number, since it is larger than the sum of its proper divisors (1).

134043320221 is an equidigital number, since it uses as much as digits as its factorization.

134043320221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 134043320221 its reverse (122023340431), we get a palindrome (256066660652).

The spelling of 134043320221 in words is "one hundred thirty-four billion, forty-three million, three hundred twenty thousand, two hundred twenty-one".