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1340474374529 is a prime number
BaseRepresentation
bin10011100000011010011…
…111111011100110000001
311202010222222000201020122
4103200122133323212001
5133430242414441104
62503445545550025
7165563130120323
oct23403237734601
94663888021218
101340474374529
114775459248a4
121979621a5315
139953852bc94
1448c44b5b613
1524d073b26be
hex1381a7fb981

1340474374529 has 2 divisors, whose sum is σ = 1340474374530. Its totient is φ = 1340474374528.

The previous prime is 1340474374523. The next prime is 1340474374541. The reversal of 1340474374529 is 9254734740431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 885571338304 + 454903036225 = 941048^2 + 674465^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340474374529 - 216 = 1340474308993 is a prime.

It is not a weakly prime, because it can be changed into another prime (1340474374523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670237187264 + 670237187265.

It is an arithmetic number, because the mean of its divisors is an integer number (670237187265).

Almost surely, 21340474374529 is an apocalyptic number.

It is an amenable number.

1340474374529 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340474374529 is an equidigital number, since it uses as much as digits as its factorization.

1340474374529 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10160640, while the sum is 53.

The spelling of 1340474374529 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred seventy-four thousand, five hundred twenty-nine".