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1340474374541 is a prime number
BaseRepresentation
bin10011100000011010011…
…111111011100110001101
311202010222222000201021002
4103200122133323212031
5133430242414441131
62503445545550045
7165563130120341
oct23403237734615
94663888021232
101340474374541
11477545924905
121979621a5325
139953852bca3
1448c44b5b621
1524d073b26cb
hex1381a7fb98d

1340474374541 has 2 divisors, whose sum is σ = 1340474374542. Its totient is φ = 1340474374540.

The previous prime is 1340474374529. The next prime is 1340474374559. The reversal of 1340474374541 is 1454734740431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1067562166441 + 272912208100 = 1033229^2 + 522410^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340474374541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340474374501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670237187270 + 670237187271.

It is an arithmetic number, because the mean of its divisors is an integer number (670237187271).

Almost surely, 21340474374541 is an apocalyptic number.

It is an amenable number.

1340474374541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340474374541 is an equidigital number, since it uses as much as digits as its factorization.

1340474374541 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2257920, while the sum is 47.

The spelling of 1340474374541 in words is "one trillion, three hundred forty billion, four hundred seventy-four million, three hundred seventy-four thousand, five hundred forty-one".